Operations on spans

Content created by Egbert Rijke.

Created on 2024-01-28.
Last modified on 2024-01-28.

module foundation.operations-spans where

open import foundation-core.operations-spans public
Imports
open import foundation.dependent-pair-types
open import foundation.equivalences-arrows
open import foundation.morphisms-arrows
open import foundation.spans
open import foundation.universe-levels

open import foundation-core.function-types

Idea

This file contains some further operations on spans that produce new spans from given spans and possibly other data. Previous operations on spans were defined in foundation-core.operations-spans.

Definitions

Concatenating spans and equivalences of arrows on the left

Consider a span s given by

       f       g
  A <----- S -----> B

and an equivalence of arrows h : equiv-arrow f' f as indicated in the diagram

          f'
     A' <---- S'
     |        |
  h₀ | ≃    ≃ | h₁
     V        V
     A <----- S -----> B.
          f       g

Then we obtain a span A' <- S' -> B.

module _
  {l1 l2 l3 l4 l5 : Level} {A : UU l1} {B : UU l2}
  (s : span l3 A B)
  {S' : UU l4} {A' : UU l5} (f' : S'  A')
  (h : equiv-arrow f' (left-map-span s))
  where

  spanning-type-left-concat-equiv-arrow-span : UU l4
  spanning-type-left-concat-equiv-arrow-span = S'

  left-map-left-concat-equiv-arrow-span :
    spanning-type-left-concat-equiv-arrow-span  A'
  left-map-left-concat-equiv-arrow-span = f'

  right-map-left-concat-equiv-arrow-span :
    spanning-type-left-concat-equiv-arrow-span  B
  right-map-left-concat-equiv-arrow-span =
    ( right-map-span s) 
    ( map-domain-equiv-arrow f' (left-map-span s) h)

  left-concat-equiv-arrow-span :
    span l4 A' B
  pr1 left-concat-equiv-arrow-span =
    spanning-type-left-concat-equiv-arrow-span
  pr1 (pr2 left-concat-equiv-arrow-span) =
    left-map-left-concat-equiv-arrow-span
  pr2 (pr2 left-concat-equiv-arrow-span) =
    right-map-left-concat-equiv-arrow-span

Concatenating spans and equivalences of arrows on the right

Consider a span s given by

       f       g
  A <----- S -----> B

and a morphism of arrows h : hom-arrow g' g as indicated in the diagram

               g'
           S' ----> B'
           |        |
        h₀ | ≃    ≃ | h₁
           V        V
  A <----- S -----> B.
       f       g

Then we obtain a span A <- S' -> B'.

module _
  {l1 l2 l3 l4 l5 : Level} {A : UU l1} {B : UU l2}
  (s : span l3 A B)
  {S' : UU l4} {B' : UU l5} (g' : S'  B')
  (h : equiv-arrow g' (right-map-span s))
  where

  spanning-type-right-concat-equiv-arrow-span : UU l4
  spanning-type-right-concat-equiv-arrow-span = S'

  left-map-right-concat-equiv-arrow-span :
    spanning-type-right-concat-equiv-arrow-span  A
  left-map-right-concat-equiv-arrow-span =
    ( left-map-span s) 
    ( map-domain-equiv-arrow g' (right-map-span s) h)

  right-map-right-concat-equiv-arrow-span :
    spanning-type-right-concat-equiv-arrow-span  B'
  right-map-right-concat-equiv-arrow-span = g'

  right-concat-equiv-arrow-span :
    span l4 A B'
  pr1 right-concat-equiv-arrow-span =
    spanning-type-right-concat-equiv-arrow-span
  pr1 (pr2 right-concat-equiv-arrow-span) =
    left-map-right-concat-equiv-arrow-span
  pr2 (pr2 right-concat-equiv-arrow-span) =
    right-map-right-concat-equiv-arrow-span

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